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8x^2-6x^2-23x+6=0
We add all the numbers together, and all the variables
2x^2-23x+6=0
a = 2; b = -23; c = +6;
Δ = b2-4ac
Δ = -232-4·2·6
Δ = 481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-23)-\sqrt{481}}{2*2}=\frac{23-\sqrt{481}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-23)+\sqrt{481}}{2*2}=\frac{23+\sqrt{481}}{4} $
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